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Welcome to Wordfeud League of Honour! We arrange tournaments in Wordfeud and several other games. Read the details under 'Rules', and join us under 'Sign up'!

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League: Season: Division: Group: Player:

PlassNavnSpiltSeierUavgjTapScore for-motMarginPoengFra
1Hummelgumman 6 5012083 - 176631710
2ingvaldsdottir 6 4022322 - 21811418
3ingran2 6 3121502 - 10094937
4klaraprov2 6 3031512 - 1586-746
5bmljunggren 6 303994 - 1223-2296
6Fjompas 6 2131342 - 11002425Stockholm
7doit50 6 006263 - 1153-8900
1Hummelgumman+31710
Spilt: 6
Seier: 5
Uavgjort: 0
Tap: 1
Score: 2083 - 1766
2ingvaldsdottir+1418
Spilt: 6
Seier: 4
Uavgjort: 0
Tap: 2
Score: 2322 - 2181
3ingran2+4937
Spilt: 6
Seier: 3
Uavgjort: 1
Tap: 2
Score: 1502 - 1009
4klaraprov2-746
Spilt: 6
Seier: 3
Uavgjort: 0
Tap: 3
Score: 1512 - 1586
5bmljunggren-2296
Spilt: 6
Seier: 3
Uavgjort: 0
Tap: 3
Score: 994 - 1223
6Fjompas+2425
Spilt: 6
Seier: 2
Uavgjort: 1
Tap: 3
Score: 1342 - 1100
Fra: Stockholm
7doit50-8900
Spilt: 6
Seier: 0
Uavgjort: 0
Tap: 6
Score: 263 - 1153

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Comments

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Navn Melding Tid
LoBotIn Säsong 172 Div 10, Grupp 16 , Hummelgumman has won the group easily. This is no surprise to us Bots, Hummelgumman belongs in quite another level in the league system. 23/01 2019 13:30:54
LoBotHere we have an amazing gang! HUMMELGUMMAN is the player with the highest average score in a season (only counting the last 25 seasons), with 424 points per match (it happened in season 165 in division 9.) KLARAPROV2 is the secondmost experienced player in the group, and has played continously since the debut in season 141. DOIT50 is a outstanding player who has been number 3 in division 10 in season 158. FJOMPAS is a superb opponent who was number 3 on this level last season. BMLJUNGGREN is the tactically strongest player of the last 25 seasons, the opponents have merely scored the humble average of 173 points per game. INGRAN2 is a amazing player who has been number 8 in division 9 in season 166. INGVALDSDOTTIR is a amazing player who has been number 8 in division 9 in season 171.

If I were to guess, I would say that Hummelgumman ends up as the winner here.

9/01 2019 13:58:37

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Matches

Kamp Resultat
HUMMELGUMMAN
Hummelgumman – Fjompas363 – 332
Hummelgumman – ingvaldsdottir407 – 360
Hummelgumman – klaraprov2392 – 278
Hummelgumman – ingran2386 – 346
Hummelgumman – bmljunggren385 – 450
Hummelgumman – doit50150 – 0
FJOMPAS
Fjompas – Hummelgumman332 – 363
Fjompas – ingvaldsdottir373 – 376
Fjompas – klaraprov2337 – 361
Fjompas – ingran20 – 0
Fjompas – bmljunggren150 – 0
Fjompas – doit50150 – 0
INGVALDSDOTTIR
ingvaldsdottir – Hummelgumman360 – 407
ingvaldsdottir – Fjompas376 – 373
ingvaldsdottir – klaraprov2389 – 356
ingvaldsdottir – ingran2406 – 388
ingvaldsdottir – bmljunggren388 – 394
ingvaldsdottir – doit50403 – 263
KLARAPROV2
klaraprov2 – Hummelgumman278 – 392
klaraprov2 – Fjompas361 – 337
klaraprov2 – ingvaldsdottir356 – 389
klaraprov2 – ingran2217 – 468
klaraprov2 – bmljunggren150 – 0
klaraprov2 – doit50150 – 0
INGRAN2
ingran2 – Hummelgumman346 – 386
ingran2 – Fjompas0 – 0
ingran2 – ingvaldsdottir388 – 406
ingran2 – klaraprov2468 – 217
ingran2 – bmljunggren150 – 0
ingran2 – doit50150 – 0
BMLJUNGGREN
bmljunggren – Hummelgumman450 – 385
bmljunggren – Fjompas0 – 150
bmljunggren – ingvaldsdottir394 – 388
bmljunggren – klaraprov20 – 150
bmljunggren – ingran20 – 150
bmljunggren – doit50150 – 0
DOIT50
doit50 – Hummelgumman0 – 150
doit50 – Fjompas0 – 150
doit50 – ingvaldsdottir263 – 403
doit50 – klaraprov20 – 150
doit50 – ingran20 – 150
doit50 – bmljunggren0 – 150
HUMMELGUMMAN
Hummelgumman363
Fjompas332
Hummelgumman407
ingvaldsdottir360
Hummelgumman392
klaraprov2278
Hummelgumman386
ingran2346
Hummelgumman385
bmljunggren450
Hummelgumman150
doit500
FJOMPAS
Fjompas332
Hummelgumman363
Fjompas373
ingvaldsdottir376
Fjompas337
klaraprov2361
Fjompas0
ingran20
Fjompas150
bmljunggren0
Fjompas150
doit500
INGVALDSDOTTIR
ingvaldsdottir360
Hummelgumman407
ingvaldsdottir376
Fjompas373
ingvaldsdottir389
klaraprov2356
ingvaldsdottir406
ingran2388
ingvaldsdottir388
bmljunggren394
ingvaldsdottir403
doit50263
KLARAPROV2
klaraprov2278
Hummelgumman392
klaraprov2361
Fjompas337
klaraprov2356
ingvaldsdottir389
klaraprov2217
ingran2468
klaraprov2150
bmljunggren0
klaraprov2150
doit500
INGRAN2
ingran2346
Hummelgumman386
ingran20
Fjompas0
ingran2388
ingvaldsdottir406
ingran2468
klaraprov2217
ingran2150
bmljunggren0
ingran2150
doit500
BMLJUNGGREN
bmljunggren450
Hummelgumman385
bmljunggren0
Fjompas150
bmljunggren394
ingvaldsdottir388
bmljunggren0
klaraprov2150
bmljunggren0
ingran2150
bmljunggren150
doit500
DOIT50
doit500
Hummelgumman150
doit500
Fjompas150
doit50263
ingvaldsdottir403
doit500
klaraprov2150
doit500
ingran2150
doit500
bmljunggren150